3x^2/3-4x^1/3-4=0

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Solution for 3x^2/3-4x^1/3-4=0 equation: 


x in (-oo:+oo)

(3*x^2)/3-((4*x^1)/3)-4 = 0

(3*x^2)/3+(-4/3)*x-4 = 0

x^2-4/3*x-4 = 0

DELTA = (-4/3)^2-(-4*1*4)

DELTA = 160/9

DELTA > 0

x = ((160/9)^(1/2)+4/3)/(1*2) or x = (4/3-(160/9)^(1/2))/(1*2)

x = ((160/9)^(1/2)+4/3)/2 or x = (4/3-(160/9)^(1/2))/2

x in { (4/3-(160/9)^(1/2))/2, ((160/9)^(1/2)+4/3)/2 }

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